At pick 3 at 90% it does not repeat odd / even 5/5 at the same position.

At pick 3 at 90% it does not repeat odd / even Five/Five at the same place.

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bgonçalves
Brasil
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June nine, 2010
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Posted: April 21, 2017, 7:39 pm – IP Logged

At pick 3 at 90% it does not repeat odd / even Five/Five at the same place
Par = zero,2,four,6,eight
Odd = 1,3,Five,7,nine
Example =
1st 2d third
  1 3 four
  1 zero eight
  No Repeated pair trend in 2d place
  So from the ultimate draw to the subsequent one among the 3 positions does not repeat the trend if the ultimate draw is odd in the subsequent draw shall be a couple, this might serve to have a reference

amber123's avatar - OpIFNim

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March 12, 2015
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Posted: April 21, 2017, 10:09 pm – IP Logged

At pick 3 at 90% it does not repeat odd / even Five/Five at the same place
Par = zero,2,four,6,eight
Odd = 1,3,Five,7,nine
Example =
1st 2d third
  1 3 four
  1 zero eight
  No Repeated pair trend in 2d place
  So from the ultimate draw to the subsequent one among the 3 positions does not repeat the trend if the ultimate draw is odd in the subsequent draw shall be a couple, this might serve to have a reference

Nice statement. In Florida, many pairs repeat incessantly, not such a lot the subsequent draw, however skip one, or two skips most commonly. I’ve a device for pair research that works smartly. 

It is beneath, It’s a excellent device with states that behave with out breaking regulations like pre-tests. Green laugh

https://www.lotterypost.com/thread/296694

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bgonçalves
Brasil
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June nine, 2010
2263 Posts
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Posted: April 21, 2017, 10:57 pm – IP Logged

Hello amber123, adequate, however the bjetivo
Is to peer the trend of not repeating in place Five/Five
So we will be able to paintings with Five digits
  Example when it is odd = 1,3,Five,7,nine
  Or par zero,2,four,6,eight
Let’s have a reference
  Example ultimate draw
458
  subsequent
156
In the 1st place did not repeat
  That is, we had Five choices 1,3,Five,7,nine
Happened the digit 1
  So we will be able to have a reference clear out of not repeating the Five/Five trend in the place,

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bgonçalves
Brasil
Member #92564
June nine, 2010
2263 Posts
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Posted: April 22, 2017, eight:33 am – IP Logged

Ok let’s stipulate the inexperienced for odd and blue for the couple,
  Goal to peer highlighted in blue and inexperienced pairs / odd colours
  Below the ultimate to the best of a pick3 checklist
Odd = inexperienced
Pairs = blue
458
155
289
752
153
753
456
….
Always from ultimate to subsequent
  Example of
458 to 155
In third position did not repeat the trend, modified from inexperienced to blue pair
  Doing in excel 2010 or upper
  From a listing of a variety of sweepstakes, you’ll be able to randomly create the checklist

Updated: August 19, 2017 — 6:45 pm

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